Answer:
A. [tex] T= \frac{KP^2}{Z}[/tex]
D. K = 8
B. 216
Step-by-step explanation:
Q. T varies directly as the square of P and inversely as Z and T=12 when P=3 and Z=6
Solution:
According to the given information:
T varies directly as the square of P.
[tex] T\alpha P^2..... (1)[/tex]
T varies inversely as Z.
[tex] T\alpha \frac{1}{Z} ..... (2)[/tex]
Combining equations (1) & (2)
[tex] T\alpha \frac{P^2}{Z}[/tex]
[tex] T= \frac{KP^2}{Z}[/tex]
(Where K is proportionality constant)
(This is the equation of variation)
Plug T=12, P=3 and Z=6 in the above equation of variation, we find:
[tex] 12= \frac{K(3)^2}{6}[/tex]
[tex] 12= \frac{K\times 9}{6}[/tex]
[tex] K= \frac{12\times 6}{9}[/tex]
[tex] K= \frac{72}{9}[/tex]
[tex] K= 8[/tex]
So, the value of the variation constant = 8
Next, plug P=9, Z=6 and K = 8 in the above equation of variation, we find:
[tex] T= \frac{8(9)^2}{6}[/tex]
[tex] T= \frac{8\times 81}{6}[/tex]
[tex] T= \frac{648}{6}[/tex]
[tex] T= 108[/tex]
[tex] 2T= 2\times 108[/tex]
[tex] 2T= 216[/tex]
So, 216 is twice the value of T.
