Answer:
79.4° to the nearest tenth of a degree
Step-by-step explanation:
You are trying to find the angle opposite the side of length 27.
Let the length of that side be c and a and b be the lengths of the other two sides and let C be the measure of the angle you are looking for
Using the law of cosines
[tex]c = \sqrt{a^{2} + b^{2} - 2abcos C}[/tex]
[tex]27 = \sqrt{19^{2} + 23^{2} - 2(19)(23)cosC}[/tex]
[tex]27^{2} = 19^{2} + 23^{2} - 2(19)(23)cosC[/tex]
729 = 361 + 529 - 874cosC
729 = 890 - 874cosC
-161 = -874cosC
-161/-874 = cosC
.1842105.... = cosC
C = arccos .1842105.... = 79.4° to the nearest tenth of a degree
