Two sides of a right triangle measure 7 units and 3 units.

What is the area of the square that shares a side with the third side of the triangle?

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Аноним Аноним · Answer 1 · 2021-02-17T16:31:36+01:00

Answer:

20 units squared

Step-by-step explanation:

Use pythagorean theorem to find third side of triangle

[tex] {2}^{2} + 4 {}^{2} = {x}^{2} [/tex]

[tex]4 + 16 = {20} [/tex]

Take the sqr root of 20

[tex] \sqrt{20} [/tex]

So the side of the square is sqr root of 20

Area is length x width

The area of a square is 2 times s, where s is the length of one side since a square sides are all equal.

So

[tex] \sqrt{20} \times \sqrt{20 } = 20[/tex]

andromache andromache · Answer 2 · 2022-04-20T13:28:30+02:00

The area of the square that shares a side with the third side of the triangle should be considered as the 58 .

Since Two sides of a right triangle measure 7 units and 3 units.

So here the third side be

[tex]= \sqrt{7^2 + 3^2}\\\\ = \sqrt{49 + 9} \\\\= \sqrt{58}[/tex]

So here area of the square should be considered as 58.

Learn more about an area here: https://brainly.com/question/24417940