The net reaction of the cell:
[tex]Cd+Cu^{2+}\rightarrow Cd^{2+}+Cu[/tex]
Given:
A cell diagram of an electrochemical cell:
[tex]Cd | Cd^{2+} | | Cu^{2+} | Cu[/tex]
To find:
The net reaction.
Solution:
[tex]Cd | Cd^{2+} | | Cu^{2+} | Cu[/tex]
The first member from the left side in the cell diagram represents the anode electrode.
At the anode, oxidation reaction takes place:
[tex]Cd\rightarrow Cd^{2+}+2e^-...[1][/tex]
║ = Salt bridge connecting two half cells
The last member of the cell diagram represents the cathode electrode.
At the cathode, a reduction reaction takes place:
[tex]Cu^{2+}+2e^-\rightarrow Cu...[2][/tex]
The net reaction of the cell:
[1]+[2]=
[tex](Cd\rightarrow Cd^{2+}+2e^-)\\\\+\\\\(Cu^{2+}+2e^-\rightarrow Cu)[/tex]
[tex]Cd+Cu^{2+}\rightarrow Cd^{2+}+Cu[/tex]
The net reaction of the cell:
[tex]Cd+Cu^{2+}\rightarrow Cd^{2+}+Cu[/tex]
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