Answer:
The remainder must be 3
when z(x) is divided by (x+6)
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Explanation:
The remainder theorem says that if you divide p(x) over (x-k), then the remainder is r = p(k)
Now if z(-6) = 3, then we can see that k = -6 and r = 3.
So we'll divide z(x) over x-k = x-(-6) = x+6 to get some quotient and then a remainder of r = 3.
