Respuesta :

Step-by-step explanation:

In the given triangle,

Perpendicular = d

Hypotenuse = e

Base = f

We need to find the values of sinx, tanx and cosx.

We know that,

[tex]\sin \theta=\dfrac{P}{H}\\\\\tan\theta=\dfrac{P}{B}\\\\\cos\theta=\dfrac{B}{H}[/tex],

We have, P = d, H = e and base = f

So,

[tex]\sin \theta=\dfrac{d}{e}\\\\\tan\theta=\dfrac{d}{f}\\\\\cos\theta=\dfrac{f}{e}[/tex]

Hence, this is the required solution.

akposevictor

Using the lengths given, the Trigonometry ratios of the right triangle are:

  • sin x = d/e
  • cos x = f/e
  • tan x = d/f

Recall:

  • In a right triangle where we are given a reference angle, ∅, with three sides, we can solve the triangle using the Trigonometry ratios given as: SOH CAH TOA.

Given the following:

  • ∅ = x
  • Opposite = d
  • Hypotenuse = e
  • Adjacent = f

Thus:

sin x = Opp/Hyp = d/e (SOH)

cos x = adj/Hypo = f/e (CAH)

tan x = Opp/Adj = d/f (TOA)

Therefore, using the lengths given, the Trigonometry ratios of the right triangle are:

  • sin x = d/e
  • cos x = f/e
  • tan x = d/f

Learn more about Trigonometry ratios on:

https://brainly.com/question/4326804

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