A gas in a piston starts out with a volume of 156 mL, a temperature of 28.1° C, and a pressure of 1.12 atm. If it ends with a volume of 312 mL and a temperature of 87.2° C, what is the new pressure?

Answer:
0.67atm is the new pressure of the gas
Explanation:
To find one condition of a gas when pressure, volume and absolute temperature change we must use combined gas law:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
Where P is pressure, V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.
Replacing:
P₁ = 1.12atm
V₁ = 156mL
T₁ = 28.1°C + 273.15K = 301.25K
P₂ = ?
V₂ = 312mL
T₂ = 87.2°C + 273.15 = 360.35K
1.12atm*156mL / 301.25K = P₂*312mL / 360.35K
P₂ = 0.67atm is the new pressure of the gas