Answer:
62.8
Step-by-step explanation:
To find the area of metal required, we calculate the area of the outer circle and subtract the area of the two inner semicircles. The area of the outer circle is,
AOC=πr2=π(62)=113.0973 in2
The area of the inner semicircles is,
AIC=2⋅12πr2=π(42)=50.26548 in2
The total area of the sign is,
A=113.0973−50.26548=62.83182 in2
Rounded to one decimal place, the area of metal required is 62.8 square inches.
5rdc
The area of metal required is 62.8 square inches.
The area of a circle is the area covered by the circle in a two dimensional plane .
Area of the outer circle is,
=[tex]\pi[/tex]r²=[tex]\pi[/tex](6²)=113.04 square inches
The area of the inner semicircles is,
=[tex]\pi[/tex](4)²=50.24 square inches
The total area of the sign is,
=113.04−50.24=62.8 square inches
Hence, the area of metal required is 62.8 square inches.
Learn more about area of a circle
https://brainly.com/question/27683633
#SPJ2
