Answer:
18.58
Explanation:
From the question given above, the following data were:
Isotope A:
Abundance of A = 54%
Mass of A = 17.984 amu
Isotope B:
Abundance of B = 32%
Mass of B = 18.985 amu
Isotope C:
Abundance of C = 14%
Mass of C = 19.982 amu
Average atomic mass =?
AVERAGE = [(Mass of A × A%)/100)] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]
AVERAGE = [(17.984 × 54%)/100] + [(18.985 × 32%)/100] + [(19.982 × 14%)/100]
= 9.71136 + 6.0752 + 2.79748
= 18.58
Therefore, the average atomic mass of the isotope is 18.58 amu
