Respuesta :

y=5x+b
substitute in the equation with the point that is given to get the y intercept, so :
11=5(-2)+b
11=-10+b
21=b
since the slope is 5 and the y intercept is 21, so the equation will be :
y=5x+21

hope this helps !

The required equation of the line whose slope is 5 and passes through the point (-2, 11) is (y - 11) = 5(x+2) or y = 5x + 21.

An equation for the line whose slope is 5 and which passes through the point ( –2, 11) is to determined.

What is a Line??

A line can be defined by the shortest distance between two points is called a line. The standard equation of the line is y =mx + c, where m and c are the slope and y-intercept of the line respectively.

Slope ( m ) = 5 and an ordered pair ( -2 , 11 ) is given in question
Equation of line is given as
[tex]y-y_1= m(x-x_1)\\[/tex]
y - 11 = 5 (x + 2)
y - 11 = 5x + 10
y = 5x + 10 +11
y = 5x + 21

Thus, the required equation of the line whose slope is 5 and passes through the point (-2, 11) is (y - 11) = 5(x+2) or y = 5x + 21.

Learn more about lines here:

brainly.com/question/2696693

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