Need help ASAP!!!!!! It says that I am supposed to find the perimeter of triangle DBC.

Answer:
Step-by-step explanation:
AC=[tex]\sqrt{20^{2} -12^{2} }[/tex]
AC=16
BC=16-10
BC=6
BD=[tex]\sqrt{12^{2} +6^{2} }[/tex]
BD=13.42(correct to nearest hundredth)
The perimeter of ΔDBC=13.42+6+12
= 31.42