Answer:
a.
[tex]M_{CaBr_2}=40.08+79.9*2=199.88 g/mol[/tex]
b.
[tex]M_{BeBr_2}=9.012+79.9*2=168.81g/mol[/tex]
c.
[tex]M_{CdBr_2}=112.41+79.9*2=272.21g/mol[/tex]
d.
[tex]M_{CuBr_2}=63.55+79.9*2=223.35g/mol[/tex]
Explanation:
Hello!
In this case, since the molar mass of a compound is computed by adding the molar mass of each element composing it and multiplying it by the number of atoms in the molecule, we have:
a.
[tex]M_{CaBr_2}=40.08+79.9*2=199.88 g/mol[/tex]
b.
[tex]M_{BeBr_2}=9.012+79.9*2=168.81g/mol[/tex]
c.
[tex]M_{CdBr_2}=112.41+79.9*2=272.21g/mol[/tex]
d.
[tex]M_{CuBr_2}=63.55+79.9*2=223.35g/mol[/tex]
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