Answer:
34.02 g.
Explanation:
Hello!
In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:
[tex]PV=nRT\\\\n=\frac{1.00atm*0.960L}{0.08206\frac{atm*L}{mol*K}*(150+273)K} =0.0277mol\\\\[/tex]
Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:
[tex]MM=\frac{0.941g}{0.0277mol} \\\\MM=34.02g/mol[/tex]
So probably, the gas may be H₂S.
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