Respuesta :

lkrepp

Answer:

x = 3

x - 2y = -25

Step-by-step explanation:

Since y = 4x + 2 put (4x + 2) into the first equation in place of y:

6x - (4x + 2) = 4

To get rid of the parenthesis change 4x to -4x and 2 to -2:

6x - 4x - 2 = 4

If you combine the x’s you will now have only 2x

2x - 2 = 4

To get x by itself we add 2 to both sides

2x = 6

Divide by 2 on both sides:

x = 3

_______________________________

For the last equation (x - 2y) we put (4x + 2) in place of y again:

x - 2[4x + 2]

We know the value of x already:

3 - 2[4(3) + 2]

Now solve for the things in parenthesis:

3 - 2(14)

3 - 28

Subtract to get the answer:

-25

ilovejiminssi

Answer:

[tex]Point Form:(1,2)\\Equation Form:x=1,y=2[/tex]

Step-by-step explanation:

Let's solve your system by substitution.

[tex]6x-y=4;y=4x+2x-2y[/tex]

Step: Solve 6x−y=4for y:

[tex]6x-y=46x-y+-6x=4+-6x[/tex]

[tex]-y=-6x+4[/tex]

[tex]\frac{-y}{-1} =\frac{-6x+4}{-1}[/tex]

[tex]y=6x-4[/tex]

Step: Substitute 6x−4 for y in y=6x−2y:

[tex]y=6x-2y\\6x-4=6x-2(6x-4)[/tex]

[tex]6x-4=-6x+8[/tex]

[tex]6x-4+6x=-6x+8+6x\\12x-4=8\\12x-4+4=8+4[/tex]

[tex]12x=12\\\frac{12x}{12} =\frac{12}{12}[/tex]

Step: Substitute 1 for x in y=6x−4:

[tex]y=6-4\\y=(6)(1)-4\\y=2[/tex]

Answer:

[tex]x=1 , y=2[/tex]

Hope this helps :)

-ilovejiminssi♡

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