Answer:
f(g(x))- 1/x^3-1
1/7
Step-by-step explanation:
Given the functions defines by;
f(x) = 1/x - 1
g(x) = x^3
a) Find f(g(x))
f(g(x)) = f(x^3)
Replace x with x^3 in f(x) as shown;
f(x^3) = 1/x^3 - 1
f(g(x))- 1/x^3-1
b) Substitute x = 2 into the result;
f(g(2)) = 1/2^3 - 1
f(g(2)) = 1/8-1
f(g(2)) = 1/7
Hence f(g(2)) = 1/7
