Answer:
The function in the form y = mx+b will be:
y = x + 3.8
Step-by-step explanation:
We know that the slope-intercept form of the line equation
[tex]y = mx+b[/tex]
where
Given the points
Determining the slope between (-6.4, -2.6 )and (5.2,9)
[tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(-6.4,\:-2.6\right),\:\left(x_2,\:y_2\right)=\left(5.2,\:9\right)[/tex]
[tex]m=\frac{9-\left(-2.6\right)}{5.2-\left(-6.4\right)}[/tex]
Refine
[tex]m=1[/tex]
substituting (5.2, 9) and m = 1 in the slope-intercept form of the line equation
y = mx+b
9 = 1(5.2) + b
b + 5.2 = 9
b = 9 - 5.2
b = 3.8
Therefore, the value of x = 3.8
now substituting b = 3.8 and m = 1 in the slope-intercept form of the line equation
y = mx+b
y = 1(x) + 3.8
y = x + 3.8
Therefore, the function in the form y = mx+b will be:
y = x + 3.8
