While the box is at rest, the net vertical force acting on it is
∑ F = n - w = 0
where n = magnitude of the normal force (table pushing up on the box) and w = weight of the box. So we have
n = w = mg = (3.0 kg) (9.8 m/s²) = 29.4 N
The coefficient of static friction between the table and box is 0.40, so the maximum magnitude of static friction is
f = 0.40 n = 0.40 (29.4 N) = 11.76 N
which is to say, the box will not move unless a force larger than this is applied to the box.
10 N is of course smaller than 11.76 N, so the box would stay at rest, and its acceleration would remain 0 m/s².
