Respuesta :
B.) 81
sq rt of x= 12-3
sq rt of x=9
take the ^2 of both sides to get rid of the sq root
x^2= (9)^2
=81
sq rt of x= 12-3
sq rt of x=9
take the ^2 of both sides to get rid of the sq root
x^2= (9)^2
=81
Given the equation: - 4 √x - 3 = 12
solve for x;
Divide both sides by -4 in [1]; we get;
√x - 3 = -3
Squaring both sides we get;
x -3 = (3)²
or
x - 3 = 9
Add 3 both sides we get;
x - 3 + 3 = 9 + 3
Simplify:
x= 12
Extraneous solution states that it is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.
Substitute x= 12 in [1]
- 4√12 - 3 = 12
- 4√9 = 12
-4. 3 = 12
-12 = 12 False.
Therefore, the value of x is 12 and it is an extraneous solution.
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