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Suppose that 25,0 mL of a gas at 725 mmHg and 298K is converted to
273'K and 760 mmHg atm. What would be the new volume? Hinto use the
following gas law equation (p1"V1) /T1 = (p2*V2)/72 "SHOW WORK *
28.15 ml
25.18 ml
21.85 mL
Particles of a liquid"

Suppose that 250 mL of a gas at 725 mmHg and 298K is converted to 273K and 760 mmHg atm What would be the new volume Hinto use the following gas law equation p1 class=

Respuesta :

ardni313

The new volume : 21.85 ml

Further explanation

Given

V1=25,0 ml

P1=725 mmHg

T1=298K is converted to

T2=273'K

P2=760 mmHg atm

Required

V2

Solution

Combined gas law :

[tex]\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}[/tex]

Input the value :

V2=(P1.V1.T2)/(P2.T1)

V2=(725 x 25 ml x 273)/(760 x 298)

V2=21.85 ml

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