Answer:
44.8L of hydrogen gas
Explanation:
The reaction expression is given as:
2Na + 2H₂O → 2NaOH + H₂
Given parameters:
Mass of sodium = 92.4g
Unknown:
Volume of hydrogen gas = ?
Solution:
To solve this problem:
1 mole of a substance at STP occupies a volume of 22.4L
Let us find the number of moles of the hydrogen gas;
Number of moles of Na = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of Na = 23g/mol
Number of moles = [tex]\frac{92.4}{23}[/tex] = 4.02mole
From the balanced reaction expression:
2 mole of Na will produce 1 mole of hydrogen gas
4.02 mole of Na will produce [tex]\frac{4.02}{2}[/tex] = 2mole of hydrogen gas
So
1 mole of a substance at STP occupies a volume of 22.4L
2 mole of hydrogen gas will occupy a volume of 2 x 22.4 = 44.8L of hydrogen gas
