The value of sin(0) should be considered as the [tex]\sqrt{5} \div 5[/tex]
Since the equation is [tex]cos(0)= -2\sqrt 5/5[/tex]
Also in the case when 0 is an angle in quadrant II
So based on this, we can say that value of sin(0) should be considered as the [tex]\sqrt{5} \div 5[/tex]
Learn more about an equation here: https://brainly.com/question/4874021
