Given: EFGH is a rectangle
Prove: Segment FH is congruent to Segment GE

Answer:
Step-by-step explanation:
Statements Reasons
1). FGH is a rectangle 1). Given
2). EFGH is a parallelogram 2). a. All rectangles are parallelogram
3). EF ≅ b. GH 3). Opposite sides of a parallelogram are
equal in measure
4). EH ≅ EH 4). c. Reflexive property
5). ∠FEH and ∠GHE are the 5). d. Property of a rectangle
right angles
6). ∠FEH ≅ e. ∠GHE 6). Right angle theorem
7). ΔFEH ≅ ΔGHE 7). f. SAS postulate of congruence
8). FH ≅ GE 8). g. CPCTC (corresponding parts of
congruent triangles are congruent)