What is the length of side EF in the triangle? Please give a step by step explanation, I'm having lots of trouble finding the solution. Thank you!

Answer:
EF = 8.8 cm
Step-by-step explanation:
In the given right angled ΔDEF, DE is the hypotenuse while EF and DF are adjacent sides. So that applying the Pythagoras theorem, we have;
[tex]/hyp/^{2}[/tex] = [tex]/adj1/^{2}[/tex] + [tex]/adj2/^{2}[/tex]
[tex]/DE/^{2}[/tex] = [tex]/EF/^{2}[/tex] + [tex]/DF/^{2}[/tex]
[tex]/16.2/^{2}[/tex] = [tex]/EF/^{2}[/tex] + [tex]/13.6/^{2}[/tex]
262.44 = [tex]/EF/^{2}[/tex] + 184.96
[tex]/EF/^{2}[/tex] = 262.44 - 184.96
= 77.48
EF = [tex]\sqrt{77.48}[/tex]
= 8.8023
EF = 8.8 cm
The length of side EF is 8.8 cm.