Answer:
Explanation:
Given that,
- Initial velocity of the stone (u) = 20.0 m/s
- Acceleration due to gravity (g)= -9.8 m/s² [upward motion]
- Final velocity of the stone [tex]\sf{(v_{max})=0\:m/s}[/tex]
We know that,
[tex]{\boxed{\sf{v=u+gt}}}[/tex]
[ Put values ]
[tex]\begin{gathered} \implies \sf \: {0} \: = {20} + ( - 9.8) \times t \\ \\ \implies \sf \: 0 = 20 - 9.8t \\ \\ \implies \sf \: 9.8t = 20 \\ \\ \implies \sf \: t = \dfrac{20}{9.8} \\ \\ \implies \sf \: t = 2.04\end{gathered}[/tex]
Therefore, the time at which the stone reaches its maximum height will be 2.04 s.
