Answer:
See explanation.
Explanation:
Hello!
In this case, since the main molecular reaction that is taken place in the beaker is:
[tex]AgNO_3(aq)+BaI_2(aq)\rightarrow AgI(s)+Ba(NO_3)_2(aq)[/tex]
In such a way, we understand that one breaker contained silver nitrate and the other one barium iodide. Thus, the complete molecular equations turns out:
[tex]2AgNO_3(aq)+BaI_2(aq)\rightarrow 2AgI(s)+Ba(NO_3)_2(aq)[/tex]
Now, for the complete ionic equation, we just ionize the aqueous species:
[tex]2Ag^++2NO_3^-+Ba^{2+}+2I^-\rightarrow 2AgI(s)+Ba^{2+}+2(NO_3)^-[/tex]
Finally, for the net ionic equation we cancel out barium and nitrate ions as the spectator one because they are both sides on the equation:
[tex]2Ag^++2I^-\rightarrow 2AgI(s)[/tex]
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