Answer:
Empirical formula is Au₂O₃
Explanation:
Given data:
Percentage of oxygen = 11%
Percentage of gold = 89%
Empirical formula = ?
Solution:
Solution:
Number of gram atoms of O = 11 / 16 = 0.69
Number of gram atoms of Au = 89 / 197 = 0.45
Atomic ratio:
Au : O
0.45/0.45 : 0.69 /0.45
1 : 1.5
Au : O = 1 : 1.5
Au : O = 2( 1 : 1.5)
Empirical formula is Au₂O₃.
