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Hooke's law describes a certain light spring of unstretched length 31.8 cm. when one end is attached to the top of a doorframe and a 7.52 kg object is hung from the other end, the length of the spring is 40.4 cm. (a) find its spring constant. 856.9 incorrect: your answer is incorrect. your response is off by a multiple of ten. kn/m (b) the load and the spring are taken down. two people pull in opposite directions on the ends of the spring, each with a force of 188 n. find the length of the spring in this situation.

Respuesta :

Answer:

Explanation:

extension in the spring = 40.4 - 31.8 = 8.6 cm = 8.6 x 10⁻² m .

kx = mg

k is spring constant , x is extension , m is mass

k x 8.6 x 10⁻² = 7.52 x 9.8

k = 856.93 N/m

=  857 x 10⁻³ KN /m

b ) Both side is pulled by force of 188 N .

Tension in spring = 188N

kx = T

856.93 x = 188

x = .219.38 m

= 21.938 cm

= 21.9 cm .

length of spring = 31.8 + 21.9

= 53.7 cm .

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