(d) In the laboratory, the temperature is 295 K and the total pressure in the gas-collecting tube is 741.2 mmHg . If the vapor pressure of water at 295 K is 19.8 mmHg , determine the pressure of the H2(g) in the gas-collecting tube.

Respuesta :

Answer: The pressure of the hydrogen in the gas-collecting tube is 721.3 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

[tex]p_{total}=p_{H_2O}+p_{H_2}[/tex]

Given : [tex]p_{total}[/tex] =total pressure of gases = 741.1 mm Hg

[tex]p_{H_2O}[/tex] = partial pressure of water = 19.8 mm Hg

[tex]p_{H_2}[/tex] = partial pressure of hydrogen = ?

putting in the values we get:

[tex]741.1 mm Hg=19.8mmHg+p_{H_2}[/tex]  

[tex]p_{H_2}=721.3mm Hg[/tex]

Thus  the pressure of the hydrogen in the gas-collecting tube is 721.3 mm Hg

According to the Dalton Law in a blend of non-reacting gases, the entire pressure will be equivalent to the total of partial pressures of the individual gases.

The pressure of H₂ gas collected in the tube will be 721.3 mm Hg.

This can be calculated by:

Dalton's formula:

[tex]\text{p}_{\text{total}} & = \text{p}\text{H}_{2} \text{O} + \text{p} \text{H}_{2}[/tex]

Given :  

  • [tex]\text{p}_{\text{total}}[/tex] = total pressure of gases = 741.1 mm Hg

  • [tex]\text{p}\text{H}_{2} \text{O}[/tex] = partial pressure of water = 19.8 mm Hg

  • [tex]\text{p} \text{H}_{2}[/tex]= partial pressure of hydrogen = ?

Now using the formula we will calculate:

[tex]\text{741.1 mm Hg} & = \text{19.8 mm Hg} + \text{p} \text{H}_{2}[/tex]

[tex]721.3 \;\text {mm Hg} = \text{p} \text{H}_{2}[/tex]

Therefore, the pressure of the hydrogen in the tube is 721.3 mm Hg.

To learn more about Dalton Law follow the link:

https://brainly.com/question/14119417

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