Answer: 0.002 M
Explanation:
The balanced chemical equation for ionization of [tex]H_2SO_4[/tex] in water is:
[tex]H_2SO_4\rightarrow 2H^++SO_4^{2-}[/tex]
According to stoichiometry :
1 mole of [tex]H_2SO_4[/tex] ionizes to give =2 mole of [tex]H^+[/tex] ions
0.001 mole of [tex]H_2SO_4[/tex] ionizes to give = [tex]\frac{2}{1}\times 0.001=0.002[/tex] mole of [tex]H^+[/tex] ions
Thus [tex]H^+[/tex] of a solution of 0.001 M aqueous sulfuric acid is 0.002 M
