Answer:
[tex]\sin d = \frac{4}{7}[/tex] ; [tex]\sin e = \frac{\sqrt{33} }{7}[/tex]
[tex]\cos d = \frac{\sqrt{33} }{7}[/tex] ; [tex]\cos e = \frac{4}{7}[/tex]
[tex]\tan d = \frac{4}{\sqrt{33} }[/tex] ; [tex]\tan e = \frac{\sqrt{33} }{4}[/tex]
Step-by-step explanation:
For a right angled triangle with one of its angle α (alpha) :-
- [tex]\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}[/tex]
- [tex]\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}[/tex]
- [tex]\tan \alpha = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }[/tex]
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According to the question ,
1) When α (alpha) = d
- [tex]\sin d = \frac{4}{7}[/tex]
- [tex]\cos d = \frac{\sqrt{33} }{7}[/tex]
- [tex]\tan d = \frac{4}{\sqrt{33} }[/tex]
2) When α (alpha) = e
- [tex]\sin e = \frac{\sqrt{33} }{7}[/tex]
- [tex]\cos e = \frac{4}{7}[/tex]
- [tex]\tan e = \frac{\sqrt{33} }{4}[/tex]
