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An airplane comes in for a landing with a velocity 66 m/s and travels 560 m while it comes to a
stop Calculate the acceleration of the plane? (-3.9 m/s)
Proof please

Respuesta :

Lanuel

Answer:

a = -3.9m/s²

Explanation:

Given the following data;

Initial velocity = 66m/s

Displacement = 560m

To find the acceleration, we would use the third equation of motion

V² = U² + 2aS

Substituting into the equation we have

0² = 66² + 2*a*560

0 = 4356 + 1120a

-1120a = 4356

a = - 4356/1120

a = -3.9m/s²

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