The partial pressures of CH4, N2, and O2 in a sample of gas were found to be 135 mmHg, 508 mmHg, and 571 mmHg, respectively. Calculate the mole fraction of nitrogen.

Respuesta :

Answer:

0.4

Explanation:

The total pressure of the mixture is the sum of the pressures of all the gases;

Let the total pressure be PT

PT = 135 mmHg + 508 mmHg + 571 mmHg = 1214 mmHg

Partial pressure = mole fraction * total pressure

mole fraction = partial pressure/total pressure

partial pressure of nitrogen = 508 mmHg

mole fraction = 508 mmHg/1214 mmHg

mole fraction = 0.4

The proportion of the moles present in the whole amount of moles in a mixture is called a mole fraction.

In a gaseous mix, the partial pressure of single gas will be equal to the product of mole fraction and partial pressure of the particular gas.

The mole fraction of Nitrogen will be 0.4.

This can be calculated by:

  • Partial pressures of CH₄: 135 mm Hg

  • Partial pressures of N₂: 508 mm Hg

  • Partial pressures of O₂: 571 mm Hg

The total pressure will be:

= 135 mmHg + 508 mmHg + 571 mmHg

= 1214 mmHg

[tex]\text{Partial pressure} & = \text{Mole fraction} \times \text{Total Pressure}[/tex]

[tex]\text{Mole fraction} = \dfrac{\text{Partial pressure}} {\text{Total pressure}}[/tex]

[tex]\text{Mole fraction} = \dfrac{\text{508 mm Hg}} {\text{1214 mm Hg}}[/tex]

= 0.4

Therefore, mole fraction of N₂ is 0.4

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