Answer:
f(2) < g(3)
The correct option is;
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Step-by-step explanation:
The given function parameters are;
f(x) = 3·x - 1, g(x) = 2·x² - 3
For f(x) = 3·x - 1, when x = 2, we have;
f(2) = 3·x - 1 = 3 × 2 - 1 = 5
For g(x) = 2·x² - 3, when x = 3, we have;
g(3) = 2 × 3² - 3 = 18 - 3 = 15
Therefore, we have;
f(2) = 5 < g(3) = 15
Which gives;
f(2) < g(3)
