The final temperature : 191.54 K = -81.46 °C
Further explanation
Given
V₁=3.2 L
T₁ = 125 +273 = 398 K
V₂=1.54 L
Required
The final temperature(T₂)
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
T₂=(V₂T₁)/V₁
T₂=(1.54 x 398)/3.2
T₂=191.54 K = -81.46 °C
