Answer: [tex]4\dfrac{4}{9}\text{ feet per second}[/tex]
Step-by-step explanation:
Given: A frog jumps [tex]\dfrac35[/tex] feet in the span of [tex]2\dfrac23[/tex] seconds.
So, distance = [tex]\dfrac35[/tex] feet , time = [tex]2\dfrac23[/tex] seconds = [tex]\dfrac83[/tex] seconds.
Unit rate of movement = [tex]\dfrac{\dfrac83}{\dfrac35}\text{ feet per second}[/tex]
[tex]=\dfrac{40}{9}\text{ feet per second}\\\\=4\dfrac{4}{9}\text{ feet per second}[/tex]
Unit rate= [tex]4\dfrac{4}{9}\text{ feet per second}[/tex]
