Answer: Then, the end behavior of f(x) would be
f(x) → ∞ as x → - ∞ and, f(x) → -∞ as x → +∞
Step-by-step explanation:
Since we have given that
[tex]f(x)=-2(x-2)^5[/tex]
Since the degree of polynomial is 5 , which is odd.
And the leading coefficient is -2, which is negative.
Then, the end behavior of f(x) would be
f(x) → ∞ as x → - ∞
and,
f(x) → -∞ as x → +∞