If a body having mass 40kg started moving initially with rest and it takes a velocity of 20m/sec in time 4 seconds. Find the value of force​

Respuesta :

[tex]{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\[/tex]

[tex]\:\:\:\:\bullet\:\:\:\sf{Mass \ of \ the \ body \ (m) = 40 \ kg}[/tex]

[tex]\:\:\:\:\bullet\:\:\:\sf{Final \ velocity \ of \ the \ body \ (v) = 20 \ m/s}[/tex]

[tex]\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ of \ the \ body \ (u) = 0}[/tex]

[tex]\\[/tex]

[tex]{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\[/tex]

[tex]\:\:\:\:\bullet\:\:\:\sf{Force \ exerted \ by \ the \ body \ ( F)}[/tex]

[tex]\\[/tex]

[tex]{\mathfrak{\underline{\purple{\:\:\: Solution:-\:\:\:}}}} \\ \\[/tex]

Using 1st equation of motion

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{v = u + at}[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{20 = 0 + a(4)}[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{20 = 4a}[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{\dfrac{\cancel{20}}{\cancel{4}} = a}[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{a = 5}[/tex]

[tex]\\[/tex]

Now, Finding the force exerted

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{F = ma}[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{F = 40 \times 5}[/tex]

[tex]\\[/tex]

[tex]\dashrightarrow\:\: \sf{F = 200 \ N}[/tex]

[tex]\\[/tex]

Hence, [tex]\\[/tex]

[tex]\:\:\:\:\star\:\:\:\sf{The \ force \ exerted \ by \ the \ body \ is \ 200N}[/tex]

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