Answer:
Neither parallel nor perpendicular
Step-by-step explanation:
The lines represented by the equations y = 1x – 5 and 3y + x = -15 are .....
Solve for y in 3y + x = -15.
[tex]3y + x = -15 \\ \frac{ - x = - x}{3y = - x - 15} \\ \\ \frac{3y = - x - 15}{3 \: \: = \: \: \: \: \: \: \: \: \: 3} \\ y = - \frac{1}{3}x - 5[/tex]
[tex]y = - \frac{1}{3}x - 5 \: and \: y = 1x - 5[/tex]
