Answer:
0.1849
Step-by-step explanation:
Given that :
Sample size / number of trials = 100
Probability that a lamp. Is defective = 0.01
Probability that batch contains two defective lamps :
Using the binomial probability function :
P(x = x) = nCx * p^x * (1 - p)^(n-x)
P(x = 2) = 100C2 * 0.01^2 * (1 - 0.01)^(100-2)
P(x = 2) = 100C2 * 0.01^2 * 0.99^98
P(x = 2) = 4950 * 0.0001 * 0.3734642
= 0.184864779
= 0.1849
