Respuesta :
Answer:
Number of children tickets = 400
Number of students tickets = 300
Number of adults tickets = 800
Step-by-step explanation:
Let the number of children tickets = [tex]x[/tex]
Let the number of students tickets = [tex]y[/tex]
Let the number of adults tickets = [tex]z[/tex]
Total number of tickets sold = 1500
Writing the equation:
[tex]x+y+z=1500[/tex] .... (1)
Price for each children ticket = $1.50
Price for each student ticket = $3
Price for each adult ticket = $5
Total money brought in = $5500
[tex]1.5x+3y+5z = 5500[/tex] ..... (2)
Number of student tickets sold was 100 lesser than number of children's tickets.
i.e.
[tex]y = x -100[/tex] ..... (3)
Putting value of [tex]y[/tex] from (3) in equation (1) and equation (2):
[tex]x+x-100+z=1500\\\Rightarrow 2x+z=1600 .... (4)[/tex]
[tex]1.5x+3(x-100)+5z=5500\\\Rightarrow 4.5x+5z=5800 ..... (5)[/tex]
Multiplying equation (4) by 5 and subtracting equation (5) from it:
[tex]5.5x=2200\\\Rightarrow x = 400[/tex]
By equation (3):
[tex]y = 400 - 100 = 300[/tex]
By equation (1):
[tex]z = 1500 - 400 - 300 = 800[/tex]
Therefore, the answer is:
Number of children tickets = 400
Number of students tickets = 300
Number of adults tickets = 800
400 children tickets, 300 college ticket and 800 adult tickets were sold.
Let x represent the number of children tickets, y represent the number of college tickets and z represent the number of adult tickets.
Since 1500 tickets were sold, hence:
x + y + z = 1500 (1)
They brought in $5500, hence:
1.5x + 3y + 5z = 5500 (2)
Also:
y = x - 100
-x + y = -100 (3)
Solving equations 1, 2 and 3 simultaneously gives:
x = 400, y = 300, z = 800
400 children tickets, 300 college ticket and 800 adult tickets were sold.
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