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What is the distance between the points (–4, 2) and (3, –5)?

d=*square root start* (x2-x1)+(y2-y1) *Square root end*
a) square root of 10
b) square root of 28
c) square root of 98
d) square root of 117

What is the distance between the points 4 2 and 3 5 dsquare root start x2x1y2y1 Square root end a square root of 10 b square root of 28 c square root of 98 d sq class=

Respuesta :

Answer:

98

Step-by-step explanation:

D(X2-x1)^2+(Y2-y1)^2

(3-(-4)^2 +(-5-2)^2

(7)^2+(-7)^2

49+49= 98

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