Answer:
[tex]d = 2\sqrt{13}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Algebra II
- Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Step-by-step explanation:
Step 1: Define
Point (9, 3)
Point (5, -3)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d.
- Substitute [DF]: [tex]d = \sqrt{(5-9)^2+(-3-3)^2}[/tex]
- Subtract: [tex]d = \sqrt{(-4)^2+(-6)^2}[/tex]
- Exponents: [tex]d = \sqrt{16+36}[/tex]
- Add: [tex]d = \sqrt{52}[/tex]
- Simplify: [tex]d = 2\sqrt{13}[/tex]
