Describe how to transform the quantity of the fifth root of x to the seventh power, to the third powerinto an expression with a rational exponent. Make sure you respond with complete sentences.

Respuesta :

we have

[tex]((\sqrt[5]{x})^{7})^{3}[/tex]

[tex]((\sqrt[5]{x}})^{7})^{3}=((x^{\frac{1}{5}})^{7})^{3}\\\\ \\=( x^{\frac{1*7}{5}})^{3}\\ \\=x^{\frac{21}{5}}\\ \\= \sqrt[5]{x^{21}} \\ \\=\sqrt[5]{x^{5}x^{5}x^{5}x^{5}x} \\ \\=x^{4} \sqrt[5]{x}[/tex]

therefore

the answer is

[tex]x^{4} \sqrt[5]{x}[/tex]

Answer:

Hence, the transformation of the given quantity into an expression with a rational exponent is:

[tex]x^{\dfrac{21}{5}}[/tex]

Step-by-step explanation:

We are given an algebraic quantity as:

fifth root of x to the seventh power, to the third power into an expression with a rational exponent.

i.e. we have to convert the given algebraic quantity:

[tex](\sqrt[5]{x}^7)^3[/tex]

i.e. the expression could also be written as:

[tex]=(x^{\dfrac{7}{5})^3[/tex]

( since,

[tex](x^{\frac{1}{n})^m=x^{\frac{m}{n}}[/tex]

which is further represented as:

[tex]x^{\dfrac{21}{5}}[/tex]

( Since, we have:

[tex](x^m)^n=x^{mn}[/tex]

Hence, the expression is:

[tex]x^{\dfrac{21}{5}}[/tex]

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