Answer:
x = -8
Step-by-step explanation:
[tex]\frac{3}{4}(\frac{1}{4}x+8)-(\frac{1}{2}x+2) =\frac{3}{8}(4-x)-\frac{1}{4}x\\\\\frac{3}{4}*\frac{1}{4}x+\frac{3}{4}*8-\frac{1}{2}x-2 =\frac{3}{8}*4-\frac{3}{8}x-\frac{1}{4}x\\\\\frac{3}{16}x+3*2-\frac{1}{2}x-2 =\frac{3}{2}-\frac{3}{8}x-\frac{1}{4}x\\\\\\ \frac{3}{16}x+6-\frac{1}{2}x-2 =\frac{3}{2}-\frac{3}{8}x-\frac{1}{4}x\\\\\frac{3}{16}x-\frac{1}{2}x+\frac{3}{8}x+\frac{1}{4}x=\frac{3}{2}-4\\\\\\\frac{3}{16}x-\frac{1*8}{2*8}x+\frac{3*2}{8*2}x+\frac{1*4}{4*4}x=\frac{3}{2}-\frac{4*2}{1*2}\\\\\\[/tex]
[tex]\frac{3}{16}x-\frac{8}{16}x+\frac{6}{16}x+\frac{4}{16}x = \frac{3}{2}-\frac{8}{2}\\\\\frac{3-8+6+4}{16}x = \frac{3-8}{2}\\\\\frac{5}{16}x = \frac{-5}{2}\\\\x = \frac{-5}{2}*\frac{16}{5}\\\\x = -8[/tex]
