Answer: 0.79758
Step-by-step explanation:
Given that :
Mean (m) = 2.5
Variance = 0.36
Thw standard deviation = sqrt(variance) = sqrt(0.36) = 0.6
The probability of the random variable having a value less than 3 is obtained by:
P(x < 3)
Using the relation to obtain the standardized Zscore :
Z = (x - m) / s
Z = (3 - 2.5) / 0.6
Zscore = 0.8333333
p(Z < 0.833) = 0.79758 ( Z probability calculator)
