Let
x------> the price of a bike in Store B
y------> the price of a bike in Store A
we know that
[tex]y=\frac{5}{6}x[/tex] ------> equation A
[tex]y=\$150.60[/tex]
Substitute the value of y in equation A
[tex]150.60=\frac{5}{6}x[/tex]
Solve for x
Multiply by [tex]\frac{6}{5}[/tex] both sides
[tex]x=\frac{6}{5}*150.60\\\\x=\$180.72[/tex]
Find the difference of the price Store B and Store A
[tex]\$180.72-\$150.60=\$30.12[/tex]
therefore
the answer is
[tex]\$30.12[/tex]