A 40-foot ladder is leaning against a building that is 12-feet tall. What is the angle of elevation that the ladder makes with the ground? Round your answer to the nearest degree.

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Answer:

θ = 17.45°

Step-by-step explanation:

Given that,

Length of a ladder = 40 foot

Height of a building = 12 feet

We need to find the angle of elevation that the ladder makes with the ground.

40 foot will be the hypotenuse and 12 feet will be the perpendicular distance.

Using trigonometry for this:

[tex]\sin\theta=\dfrac{P}{H}\\\\\sin\theta=\dfrac{12}{40}\\\\\theta=17.457^{\circ}[/tex]

So, the angle of elevation that the ladder makes with the ground is 17.45°.

The angle of elevation is [tex]17^\circ[/tex] to the nearest degree

The right-angled triangle formed can be solved for the angle of elevation if we note that

  • The ladder forms the hypotenuse of the triangle
  • The wall of the building forms the side opposite the angle we seek

So, the trigonometric ratio to be used here is the [tex]sin\theta[/tex]. That is

[tex]sin\theta=\dfrac{\text{height of the building}}{\text{length of ladder}}[/tex]

substituting the values

[tex]sin\theta=\dfrac{12}{40}\\=\dfrac{3}{10}[/tex]

Now, to find the angle of elevation, [tex]\theta[/tex]

[tex]\theta=sin^{-1} \left(\dfrac{3}{10} \right)\\\approx 17^\circ \text{ (to the nearest degree)}[/tex]

Learn more trigonometry here: https://brainly.com/question/1980819

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