[tex]x^2+10x+22=13\\x^2+10x+22-13=0\\x^2+10x+9=0\\[/tex]
Now completing the square.
[tex](x^2+10x)+9=0\\(x^2+10x+25)+9-25=0\\(x+5)^2-16=0\\(x+5)^2=16[/tex]
(x+5)² = 16 is the rewritten equation... For first question btw.
For the solutions to the equation -
[tex]x+5=\sqrt{16},-\sqrt{16} \\x+5=4,-4\\x=4-5,-4-5\\x=-1,-9[/tex]
x = -1,-9 is the solution, for the second question.
