Given:
Cost of adult's ticket = $15
Cost of children's ticket = $8
Total tickets = 725
Total sales = $8775
To find:
The number of each type of ticket were sold.
Solution:
Let x be the number of adult tickets and y be the number of children's ticket.
Total tickets : [tex]x+y=725[/tex] ...(i)
Total sales : [tex]15x+18y=8775[/tex] ...(ii)
Multiply equation (i) by 15.
[tex]15x+15y=10875[/tex] ...(iii)
Subtract (iii) from (ii),
[tex]15x+18y-15x-15y=8775-10875[/tex]
[tex]3x=-2100[/tex]
[tex]x=-700[/tex]
Putting x=-700 in (i), we get
[tex]-700+y=725[/tex]
[tex]y=725+700[/tex]
[tex]y=1425[/tex]
Therefore, the number of adult tickets is -700 and number of child tickets is 1425.
Note: The number of tickets cannot be negative. So, there must be some error in the question.
