Answer:
C. 1400
Explanation:
The force exerted = f1 = 250
Diameter d1 = 0.02
r1 = d1/2 = 0.01
Diameter d2 = 0.15
r2 = d2/2 = 0.075
The mass of jack to lift
F1/A1 = f2/A2
250/r1² = f2/r2²
250/0.01² = f2/0.075²
When we cross multiply, we will have:
250x0.005625 = 0.0001f2
1.40625 = 0.0001f2
F2 = 1.40625/0.0001
F2 = 14062.5N
Force f = mg
g = 9.81
m = 14062.5/9.81
Mass = 1433Kg
Therefore option c is correct. A mass of 1400kg can be lifted by the jack
